Physics, asked by chiwi, 12 hours ago

The velocity of a car is increased by 60km/hour in 1min starting from rest. what is its acceleration?​

Answers

Answered by suryatalasila329
1

Answer:

Hence, The average velocity is 8.33 m/s, the acceleration is 0.278 m/s² and the distance traveled in first 1 min is 999.6 m.

Explanation:

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Answered by aravkilak07
1

Answer:

0.27 m/s^2

Explanation:

Acceleration = Change of Velocity with time i.e. {Final-Initial (Velocity)}/Time

SI Unit of Acceleration m/s^2 or ms^-2

Since the car started from rest, its initial velocity = 0

Given Final Velocity = 60 km/h

Converting 60 km/h into m/s (You can use the 5/18 formula, but for your convenience I am doing it this way)

60km x 1000 = 60000m

1hr x 60 = 60min

60min x 60 = 3600 secs

Final Velocity = 60000/3600 = 16.666666... or 16 2/3 m/s (Let's assume it to be 16.66 m/s for the convenience of calculation)

Using the derived acceleration formula (described above):

Vf - Vi/T

Putting the values:

16.66 - 0 / 60 = 16.66/60 = 0.27 m/s^2 (approximately)

Hence, the acceleration is 0.27 m/s^2

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