Question

The velocity of a car moving towards the East increases from 0 to 12ms–1 in 3.0 s. Calculate its average acceleration.

Answer 1

Given,

v1 = 0 m$s^{-1}$

v2 = 12 m$s^{-1}$

t = 3.0 sec

a =$\frac{12 ms^{-1} }{3.0 sec}$

= 4.0 m$s^{-1}$