Question

The velocity of a increases from 36km/hr to108km/h in 10s calculate the acceleration

Answer 1

u = 36 km/h = 10 m/s
v = 108 km/h = 30 m/s

Now, From 1st equation of motion,
v= u +at
⇒30 = 10 +10a
⇒10a = 20
⇒a = 2 m/s²

Answer 2

Answer:

Explanation:

Given :-

Initial Speed, u = 36 km/h = 10 m/s

Final Speed, v = 108 km/h = 30 m/s

To Find :-

Acceleration = ??

Formula to be used :-

1st equation of motion i.e v = u +at

Solution :-

Purring all values, we get

v = u + at

⇒ 30 = 10 + 10a

⇒ 10a = 20

⇒ a = 2 m/s²

Hence, the acceleration is 2 m/s².