Question

The Velocity of a moving boder increase fron
2 m/s to 12 m/s in 5 second Find the accclaration of the
bodz.​

Answer 1

Given:-

• Initial velocity ,u = 2m/s
• Final velocity ,v = 12m/s
• Time taken ,t = 5s

To Find:-

• Acceleration ,a ?

Solution:-

According to the Question

We have to calculate the acceleration of the body.

Acceleration is defined as the rate of change in velocity.

• a = v-u/t

where,

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken

Substitute the value we get

$:\implies$ a = 12-2/5

$:\implies$ a = 10/5

$:\implies$ a = 2m/s²

• Hence, the acceleration of the body is 2m/s².

Answer 2

Answer:

Appropriate Question :-

• The velocity of a moving body increase from 2 m/s to 12 m/s in 5 seconds. Find the acceleration.

Given :

• The velocity of a moving body increase from 2 m/s to 12 m/s in 5 seconds.

To Find :-

• What is the acceleration.

Formula Used :-

$\clubsuit$ First equation of motion :

$\longmapsto \sf\boxed{\bold{\pink{v =\: u + at}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time

Solution :-

Given :

$\bigstar$ Final Velocity = 12 m/s

$\bigstar$ Initial Velocity = 2 m/s

$\bigstar$ Time = 5 seconds

According to the question by using the formula we get,

$\longrightarrow \sf 12 =\: 2 + a(5)$

$\longrightarrow \sf 12 = 2 + 5a$

$\longrightarrow \sf 12 - 2 = 5a$

$\longrightarrow \sf 10 = 5a$

$\longrightarrow \sf \dfrac{\cancel{10}}{\cancel{5}} = a$

$\longrightarrow \sf 2 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 2\: m/s^2}}$

$\therefore$ The acceleration of the body is 2 m/s².