The velocity of a moving partical is given by V= 6+18t+9t^2(X in meter,t in seconds) what is it's acceleration at t=2s..
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differentiate velocity with respect to time we get acceleration.
a= 18+18t
at t=2s
a=18+18(2)
a=54 m/s^2
Mark as brainily
a= 18+18t
at t=2s
a=18+18(2)
a=54 m/s^2
Mark as brainily
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