Question

The velocity of a moving train covering a distance of 6km is given by V2=u+2as, calculate 'a' given that s=150km,u=5ms¹ and v=10ms¹

Answer 1

Answer:

• Acceleration = 0.00025 m/s²

Explanation:

Given:

• Initial Velocity (u) = 5 m/s

• Final Velocity (v) = 10 m/s

• Distance (s) = 150 km = 150000 m

To Find:

• Acceleration.

Now, we will calculate Acceleration by using 3rd equation of motion.

=> v² = u² + 2as

=> 10² = 5² + 2 × a × 150000

=> 100 = 25 + 300000a

=> 75 = 300000a

=> a = 75/300000

=> a = 0.00025 m/s²

Hence, Acceleration = 0.00025 m/s²