The velocity of a partice is given
by v= 12+3t+21t². find acceleration at t=2second
Answers
Answered by
0
Answer:
51 /
Explanation:
Given,
u= 0 (since the initial velocity of the particle is not given let us assume it starts from rest)
t= 2 seconds
then,
v= 12+ 3v+ 21v² {given}
v= 12 + 3×2+ 21×2²
v= 12+ 6+ 84
v=
∴ Acceleration, a =
=
=
=
Answered by
0
Answer:
v= 12 +3t+21t^2 at t=2sec
differentiate with recpect to x
dv\dx= d\dx(12+3t+21t^2)
a = 0+3+42t
a= 42(2)+3
a= 84+3
a= 87
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