The velocity of a particle 6m/s eastwards change to 8m/s northwards in 10s What is the magnitude of the average acceleration during this interval of time???
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ACC.=Change in velocity \Time taken
= V- U \ 10
8- 6÷10
2÷10
0.2Ans
= V- U \ 10
8- 6÷10
2÷10
0.2Ans
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