Question

The velocity of a particle along a straight line with a constant accleration a reduces to 1/5

Answer 1

Complete your Question.

Answer 2

From 3rd equation of motion we have,

s=ut+12at2

Let s9 be the displacement in 9 sec. So

s9=4×9+12×1×92

Sly,

s10=4×10+12×1×102

Distance covered in last sec

|s10−s9|=90−76.5=13.5m