the velocity of a particle at an instant is 10 ms. after 5 sec if its velocity is 20 ms find its velocity 3 sec earlier
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We can calculate acceleration as v-u/t
20-10/5=2m/s^2
Now 3sec earlier means 2 seconds after attaining 10m/s
Therefore
v=u+a*t
v=10+2*2
v=14m/s
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Answer:
4m/s will be correct answer
Explanation:
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