Question

the velocity of a particle given by v=10+2t²m/sec the average acceleration between 2 sec and 5 sec is
​

Answer 1

Answer:

Velocity when t=2s is v  

2

​  

=10+2×4=18m/s

Velocity when t=5s is v  

5

​  

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=  

Δt

Δv

​  

=  

3s

42m/s

​  

=14m/s  

2

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