Question

The velocity of a particle given by V= 2t2 - 6t. Find
(a) The average acceleration during the time interval t = 2sec and t = 3 sec.
(b) Find the time at which acceleration becomes zero.​

Answer 1

Answer:

hii budy, here is you answer

Velocity when t=2s is v

2

=10+2×4=18m/s

Velocity when t=5s is v

5

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=

Δt

Δv

=

3s

42m/s

=14m/s

2

hope it helps

be brainly