Physics, asked by jotsidhu5424, 11 months ago

the velocity of a particle in metre moving along a straight line is given by v equal to 7 plus 3T square find change in velocity in interval t equal to 2 second and T = 5 second, average acceleration in the same interval, instantaneous acceleration at equal to 4 seconds

Answers

Answered by amitnrw
3

Answer:

63 m/s

21 m/s²

24 m/s²

Explanation:

the velocity of a particle in metre moving along a straight line is given by v equal to 7 plus 3T square find change in velocity in interval t equal to 2 second and T = 5 second, average acceleration in the same interval, instantaneous acceleration at equal to 4 seconds

V = 7 + 3T²

Velocity at T = 2

V = 7 + 3*2² = 19 m/s

Velocity at T = 5 sec

V = 7 + 3*5² = 82 m/s

Change in Velocity from t = 2 to 5 sec = 82 - 19 = 63 m/s

Average acceleration =  (82 - 19)/(5-2)  = 63/3 = 21 m/s²

a = dV/dt  = 6T

a at 4 sec  = 6*4  = 24 m/s²

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