Question

The velocity of a particle is dependent on the time as v=k(t-1) where k=2m/s^2, the distance covered in first three seconds will be?

Answer 1

Answer:

Given that velocity is dependent on time in the relation, v = k ( t - 1 )

It is given that time taken is 3 seconds. We are required to find the distance.

We know that,

Distance = Speed * Time

Therefore Speed = k ( 3 - 1 )

Speed = k ( 2 )

We know that k is equal to 2 m/s^2. Substituting we get,

Speed = 2 ( 2 ) = 4 m/s

Distance = 4 m/s * 3 = 12 m

Therefore the particle would have covered 12 m in the furst three seconds.

Answer 2

$\huge\mathfrak\red{Answer:-}$

It is given that v=k(t-1)

and t=3s

As we know, distance= speed × Time

=> Speed = k(3-1) = k(2)

But, k = 2m/s

Speed= 2(2)

= 4m/s

So, distance= 4m/s × 3 = 12m/s