The velocity of a particle is dependent on the time as v=k(t-1) where k=2m/s^2, the distance covered in first three seconds will be?
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The velocity of a particle is dependent on the time as v=k(t-1) where k=2m/s^2, the distance covered in first three seconds will be?
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Kalpeshprabhakar Genius
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Given that velocity is dependent on time in the relation, v = k ( t - 1 )
It is given that time taken is 3 seconds. We are required to find the distance.
We know that,
Distance = Speed * Time
Therefore Speed = k ( 3 - 1 )
Speed = k ( 2 )
We know that k is equal to 2 m/s^2. Substituting we get,
Speed = 2 ( 2 ) = 4 m/s
Distance = 4 m/s * 3 = 12 m
Therefore the particle would have covered 12 m in the furst three seconds.
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