Question

The velocity of a particle is given by v =

2

- 6t + 7. Then the distance covered in 3

seconds is,​

Answer 1

Answer:

6-18t+21

Step-by-step explanation:

velocity=distance/time so then distance hogi 3×(2-6t+7)

Answer 2

Answer:

The distance covered in 3 is seconds is12

Step-by-step explanation:

• Velocity is defined as the displacement of the particle or a body in given time in the particular direction.
• It is a vector quantity having both magnitude and the direction.
• The given equation of the velocity is

          $v=2t^2-6t+7$

• At t=3, the distance of the particle is given by

          $v=2t^2-6t+7$

          $\frac{dy}{dt} =\int\limits^3_0 {(2t^2-6t+7)} \, dt \\y=\frac{2}{3} t^3-3t^2+7t\\y=\frac{2}{3} (3)^3-3(3)^2+7(3)\\\\y=18-27+21\\y=12$

• the distance covered in 3  seconds is12