the velocity of a particle is given by v=√49-7x .find acceleration of particle when its velocity is1m/s
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this the solution to u r question
it's 7/2
it's 7/2
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hardhik1:
where is - sign there
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v =root 49-7x
diff wrt t
dv/dt=-7dx/dt
wkt dv/dt=acceleration
therefore a=-7×1=-7m2/s(deacceleration)
diff wrt t
dv/dt=-7dx/dt
wkt dv/dt=acceleration
therefore a=-7×1=-7m2/s(deacceleration)
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