Question

The velocity of a particle is given by v = Kt², when Kis a positive constant and t is time. The particle has
Increasing acceleration
Decreasing acceleration
Increasing retardation
Decreasing retardation​

Answer 1

Answer:

increase acceleration

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

The velocity of a particle is given by v = Kt², when Kis a positive constant and t is time. The particle has

• Increasing acceleration

• Decreasing acceleration

• Increasing retardation

• Decreasing retardation

EVALUATION

Here it is given that the velocity of a particle is given by v = Kt², when K is a positive constant and t is time.

Now we have

$\displaystyle \sf{v = K {t}^{2} }$

Differentiating both sides with respect to t we get

$\displaystyle \sf{ \frac{dv}{dt} = f =2 K {t}^{} }$

Since K is a positive constant

As time increases acceleration also increases

Thus The particle has increasing acceleration

FINAL ANSWER

Hence the correct option is

Increasing acceleration

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