Question

The velocity of a particle movimg on the x axis is given by v= 2x^3 +x where v is in m/s and x is in metre. Fije its acceleration when passibg the point x=2m

Answer 1

Answer:

450 m/sec^2

Explanation:

rate of change of velocity is acceleration

a=(dv/dt)

=6x^2(dx/dt) +(dx/dt)

we also know

v=dx/dt

=v(6x^2+1)

from question we have v substituting

=(2x^3+2) (6x^2+1)

at x=2m

= (2×2^3+2) (6×2^2+1)

=450m/sec^2