Physics, asked by rubensantosh5, 8 months ago

.The velocity of a particle moving along the X-axis is given by v = p + qt3 – rt4. where t is the time. Find the dimensions of the constants p, q and r.

Answers

Answered by aaravshrivastwa
5

Given :-

v = p + qt³ - rt⁴

We will take single terms and compare with the dimension of velocity i.e. L/T.

v = p = L/T

[P] = L/T.

Now, Taking second term.

qt³ = L/T

[Q] = L/T⁴.

Again, For third term.

rt⁴ = L/T

[R] = L/T⁵

Hence,

The dimension of constant are as follow :-

[P] = L/T

[Q] = L/T⁴

[R] = L/T⁵

Some other dimensions which are necessary.

1. Density = D = [ML-³T⁰]

2. Acceleration = a = [M⁰LT-²]

3. Energy = [ML²T-²]

4. Strain = [M⁰L⁰T⁰] = No units.

5. Plank's Constant = [ML²T-¹]

6. Electric Intensity = [MLT-³A-¹]

7. Electric Potential = [ML²T-³A-¹]

8. Moment of Inertia = [ML²T⁰]

9. Surface Tension = [ML⁰T-²]

10. Frequency = [M⁰L⁰T-¹]

Answered by naman110610
0

Answer:

Explanation:

v = p + qt³ - rt⁴

We will take single terms and compare with the dimension of velocity i.e. L/T.

v = p = L/T

[P] = L/T.

Now, Taking second term.

qt³ = L/T

[Q] = L/T⁴.

Again, For third term.

rt⁴ = L/T

[R] = L/T⁵

Hence,

The dimension of constant are as follow :-

[P] = L/T

[Q] = L/T⁴

[R] = L/T⁵

Some other dimensions which are necessary.

1. Density = D = [ML-³T⁰]

2. Acceleration = a = [M⁰LT-²]

3. Energy = [ML²T-²]

4. Strain = [M⁰L⁰T⁰] = No units.

5. Plank's Constant = [ML²T-¹]

6. Electric Intensity = [MLT-³A-¹]

7. Electric Potential = [ML²T-³A-¹]

8. Moment of Inertia = [ML²T⁰]

9. Surface Tension = [ML⁰T-²]

10. Frequency = [M⁰L⁰T-¹]

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