Question

The velocity of a particle moving along the x axis varies in time according to the expression Vx =(40-5t^2)m/s, where t is in seconds, (a) Find the average accler in the time interval t=0 to t=2.0s​

Answer 1

Answer:

10m/s²

Explanation:

Vx=40-5t²

dv/dt=2×5t¹

Ax=10t

acceleration at t=0 is 0

and acceleration at t=2 is -10×2=-20m/s²

avg. acceleration=0-(-10)/2

so,

avg acceleration is 10mls²