The velocity of a particle moving along x axis is given as v=3x.Acceleration of the particle at x=2m is
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acceleration = rate of change of velocity
dv/dx = d(3x)/dx = 3
acceleration = dv/dt = (double differentiation)
a = dv/dx × Vx. = 3(3x )= 9x
acceleration, at x = 2m
= 9×2 = 18x
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18x is the right answer xd.....
I hope it helps you......
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