Question

The velocity of a particle moving along x–axis is given as v = x2 – 5x + 4 (in m/s) where x denotes the

x–coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity

of particle is zero ?​

Answer 1

Answer:

A particle A having a charge of 10-6 C is fixed in a vertical wall. A second particle B of mass 10 gm and having equal charge is suspended by silk thread of length 30 cm from the wall The point of suspension is 30 cm above the particle A . Find the angle of thread with the vertical when it stays in equilibrium A, B and point of suspension lying in same vertical plane.

sorry idont noo