Physics, asked by sauravraj2433, 1 year ago

the velocity of a particle moving along x axis is given by v=x^-5x+4 where x denotes the x coordinate of particle in metre.find the magnitude of acceleration of particle when velocity of particle is zero

Answers

Answered by harsh3374chauhan

first put the value of v=0 in the given equation
then u will get the value of x.
which is x=4 and x= 1.
now differentiate the given equation u will get
a=2x-5.finaly put the value of x =4 and x =1
so a=3 and a= -3.
hence acceleration (average,means when body came at rest)=0.
or u can simple say velocity =0 which means the body is at rest so their will be no acceleration

harsh3374chauhan: Hn ma bhi toh 0 hi kaha raha hu

harsh3374chauhan: Dhyan se answer Padho samaj jaoge

sauravraj2433: lakin aapke answer a=3 aaya tha

harsh3374chauhan: are yr answer toh dheko

harsh3374chauhan: tum samaj jaoge 3 Kase aya tha

sauravraj2433: samaj aa gaya

harsh3374chauhan: Vo 3 Esliya aya Bcz us time body accelerate kar rahe thi Fiir Vo body ne retardation kiya and stop Ho gae

harsh3374chauhan: Hm

harsh3374chauhan: so +3 acceleration and -3 retardation

harsh3374chauhan: so overall acceleration 0

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