the velocity of a particle moving along x axis is given by v=x^-5x+4 where x denotes the x coordinate of particle in metre.find the magnitude of acceleration of particle when velocity of particle is zero
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first put the value of v=0 in the given equation
then u will get the value of x.
which is x=4 and x= 1.
now differentiate the given equation u will get
a=2x-5.finaly put the value of x =4 and x =1
so a=3 and a= -3.
hence acceleration (average,means when body came at rest)=0.
or u can simple say velocity =0 which means the body is at rest so their will be no acceleration
then u will get the value of x.
which is x=4 and x= 1.
now differentiate the given equation u will get
a=2x-5.finaly put the value of x =4 and x =1
so a=3 and a= -3.
hence acceleration (average,means when body came at rest)=0.
or u can simple say velocity =0 which means the body is at rest so their will be no acceleration
harsh3374chauhan:
Hn ma bhi toh 0 hi kaha raha hu
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