The velocity of a particle moving along z axis varies with position z the magnitude of acceleration at position z=1m is
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Answer:
V²/2
Explanation:
As velocity is varying means it changes with position so
Let initial velocity (Vi) be 0
Final velocity (Vf) be V
Distance=z=1m
According to 3rd equation of motion
2aS= Vf²- Vi²
Putting the values
2a(1)=V²-0
2a=V²
a=V²/2
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