Question

The velocity of a particle moving in a circle of radius 4m is 6t2. What is its total acceleration at the end of 2s

Answer 1

Hii Dear,

◆ Answer -

a = 168 m/s^2

● Explaination -

Velocity at the end of 2 s is -

v = 6t^2

v = 6 × 2^2

v = 24 m/s

Radial acceleration at t = 2 s is calculated as -

ar = v^2 / r

ar = 24^2 / 4

ar = 144 m/s^2

Tangential acceleration at t = 2s is calculated as -

at = dv/dt

at = d(6t²)/dt

at = 6 × 2t

at = 12 × 2

at = 24 m/s^2

Total acceleration is thus -

a = ac + at

a = 144 + 24

a = 168 m/s^2

Therefore, total acceleration at the end of 2 s is 168 m/s^2.

Best luck...

Answer 2

Answer:

24 root 37

Explanation

Total acceleration = root(radial^2 + tangential^2)