Question

The velocity of a particle moving in positive x axis is according to relation v =√4x if at t=0 particle is at x=0 then the velocity and acceleration at t=2s are given as

Answer 1

Answer:

Explanation:

v=√4x = 2√x

dv/dx = 2 × 1/2 x^1/2-1

= 1/√x

a= v dv/dx =2√x × 1/√x

= 2 m/s^2

Now s = ut +1/2at^2

Given that u=0

s = 1/2 × 2 × 2^2

= 4 m

v^2 - u^2 =2as

v = √2as = √2×2×4 = 4m/s

Hence v=4m/s and a=2m/s^2

Answer 2

Answer:

Explanation:

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