Question

the velocity of a particle moving in the positive direction of x-axis is given as v^2=x. If the particle was located at origin initially, find position of particle as function of time.

Answer 1

v²=x
v=√x
dx/dt=√x
dx/√x=dt
Integrate both sides ,on the left from 0 to x onto the right from 0 to t
∫dx/√x=∫dt
√x/2=t
√x=2t
x=4t²