Question

The velocity of a particle moving in the positive direction of x-axis varies as $v=\alpha\sqrt{x}$, where $\alpha$ is positive constant. Assuming that at the moment t=0, the particle was located at x=0 the value of time dependence of the velocity and acceleration of the particle -

(a) $\frac{t}{2\alpha^2}$,$\frac{1}{2\alpha^2}$

(b) $\frac{\alpha^2t}{2}$, $\frac{\alpha^2}{2}$

(c) $\frac{2t}{\alpha^2}$, $\frac{2}{\alpha^2}$

(d) None of these​

Answer 1

Answer:

Explanation:

Given,

v=We know that v=dx/dt

Integrating both sides,we get value of x

Now, differentiating this x wrt t,we get velocity v.

Again, differentiating wrt t,we get acceleration.

So, option B is correct.

Answer 2

Answer:

hope ot is helpful to you