Question

The velocity of a particle moving on a circular path is 5 cm/s towards north at any instant. After traversing one-fourth of the path its velocity is 5 cm/s towards east. Indicate the change in velocity in a vector diagram.​

Answer 1

Answer:

Explanation:

This is how you add two vectors A⃗  and B⃗  to find their sum (resultant) C⃗ . I assume you are familiar with parallelogram law of vector addition.

(Diagram 1)

Let us now define a negative vector: A negative vector of a given vector is the vector of same magnitude (length) but of opposite direction.

(Diagram 2)

We further define the subtraction of B⃗  from A⃗  as the sum of −B⃗  and A⃗ .

(Diagram 3)

D⃗ =A⃗ −B⃗ =A⃗ +(−B⃗ )

Now to your question -

(Diagram 4)

Now take your vectors to the origin. Draw −vi→ and then find the resultant Δv⃗.

(Diagram 5)

Δv⃗ =vf→−v1→=vf→+(−v1→)  

Or |Δv⃗ |=|vf→|2+|−vi→|2−−−−−−−−−−−−√=|vf→|2+|vi→|2−−−−−−−−−−√

To find the direction of Δv⃗ , proceed as follows.

tanθ=|−vi→||vf|→=|vi→||vf|→

I suppose you can do the rest.

I am sorry that i can't get the diagram 1......