Question

The velocity of a particle moving on straight line is given as v = 3t^2 - 6t. The acceleration of particle when body is at rest-
(A) Zero
(B) 6 m/s^2
(C)-6 m/s^2
(D) Both (B) and (C)
(Answer is D. Please give me proper reason or steps for solution.)​

Answer 1

I guess this should be the method.....

Answer 2

Acceleration = dv/dt
dv/dt = 6t-6
At rest t= 0
dv/ dt = 6(0)-6 = -6 m/s^2