Question

the velocity of a particle moving with a uniform acceleration of 10 m s -2 after 5 seconds is 50 m s -1 its velocity at t is equal to four second is​

Answer 1

Given :-

Acceleration of particle = 10 m/s²

Velocity of particle after 5 s = 50 m/s

To Find :-

Velocity of particle at t id equal to four seconds.

Analysis :-

Here acceleration is said to be constant throughout the motion so we can apply equation of kinematics to solve this problem.

Firstly, we've to find the initial velocity of particle using the first equation of motion.

Then find the final velocity of particle at t id equal to four seconds.

Solution :-

We know that,

• v = Final velocity
• a = Acceleration
• u = Initial velocity
• t = Time

Using first equation of motion,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Acceleration (a) = 10 m/s²

Time (t) = 5 s

Final velocity (v) = 50 m/s

Substituting their values,

50 = u + (10)(5)

50 = u + 50

By transposing,

u = 50 - 50

u = 0 m/s

Hence, particle starts his journey from rest.

In the second case,

v' = u + at'

v' = 0 + (10)(4)

v' = 40 m/s

Therefore, velocity of particle at t id equal to four seconds is 40 m/s.

Answer 2

Answer:

D ) 40 ms-1 ( physics Clarity Achiever xB)