The velocity of a particle moving with a uniform acceleration of 10 ms−210 ms−2 after 5 s is 50 ms−150 ms−1 . Its velocity at t = 4 s is
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Case Study Based – II (Questions from 15-18) Mr. Mohanlal purchased a land which is in the shape of a quadrilateral. Its four corner points are given in the graph.
15. The distance between point B and point C is *
1 point
(A) 10 units
(B) 8 units
(C) 6 units
(D) 7 units
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=50m/s
u
2
=0
s
1
=u×t
a
2
=10m/s
2
s
1
=50t
s
2
=u
2
t+
2
1
a
2
t
2
s
2
=0+
2
1
×10×t
2
=5t
2
s
1
−s
2
=125⇒50t−5t
2
=125
⇒t
2
−10t+25=0⇒t=5
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u
2
=0
s
1
=u×t
a
2
=10m/s
2
s
1
=50t
s
2
=u
2
t+
2
1
a
2
t
2
s
2
=0+
2
1
×10×t
2
=5t
2
s
1
−s
2
=125⇒50t−5t
2
=125
⇒t
2
−10t+25=0⇒t=5
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