Question

The velocity of a particle of charge +4x10^-9 and mass 2x10^-4 kg is perpendicular to a 0.1 tesla magnetic field. If the particle's speed is 3x10^4 m/s, what is the acceleration of this particle due to magnetic field​

Answer 1

Answer:

If a be the acceleration of the particle due to only magnetic field B , then

ma=qvB

or a=

m

qvB

=

2×10

−4

(4×10

−9

)×(3×10

4

)×0.1

=0.06m/s

2