the velocity of a particle of mass 150 g changes from 8m/s to 12m/s in two second. assuming that a constant force acts on it, find the magnitude of the force
Answers
Answered by
154
force = mass × acceleration.
acceleration = change in velocity / time.
a = 12-8/ 2 = 2 m/s
m = 150 g = 0.15 kg.
since u have to convert all to S.I units or c.gs units.
i am doing it in s.i. units.
force = 0.15 × 2 kg m/s
force = 0.3 N..
acceleration = change in velocity / time.
a = 12-8/ 2 = 2 m/s
m = 150 g = 0.15 kg.
since u have to convert all to S.I units or c.gs units.
i am doing it in s.i. units.
force = 0.15 × 2 kg m/s
force = 0.3 N..
Answered by
15
Answer:
0.3N
Explanation:
Given,
mass of the particle, m=150g =0.15kg
Initial velocity, u=8m/s
Final velocity, v=12m/s
time taken, t=2s
acceleration, a=v-u/t
=12-8/2
=2m/s
force, f=m*a
=0.15*2
=0.3N answer.
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