Question

The velocity of a particle of mass 500 gram changes from 16m/s to 24m/s in 4 seconds . Assuming that a constant force acts on it find the magnitude of the force?

Answer 1

GiveN :

• Mass (m) = 500 g = 0.5 kg
• Initial velocity (u) = 16 m/s
• Final velocity (v) = 24 m/s
• Time interview (t) = 4 s

To FinD :

• Magnitude of Force

SolutioN :

Use 1st equation of motion :

$\\ \implies \sf{v \: = \: u \: + \: at} \\ \\ \\ \implies \sf{24 \: = \: 16 \: + \: a \: \times \: 4} \\ \\ \\ \implies \sf{4a \: = \: 24 \: - \: 16} \\ \\ \\ \implies \sf{4a \: = \: 8} \\ \\ \\ \implies \sf{a \: = \: \dfrac{8}{4}} \\ \\ \\ \implies \sf{a \: = \: 2} \\ \\ \\ \longrightarrow \underline{\boxed{\sf{Acceleration \: (a) \: = \: 2 \: ms^{-2}}}}$

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Now, use formula for Force :

$\\ \implies \sf{F \: = \: ma} \\ \\ \\ \implies \sf{F \: = \: 0.5 \: \times \: 2} \\ \\ \\ \implies \sf{F \: = \: 1} \\ \\ \\ \longrightarrow \underline{\boxed{\sf{Force \: = \: 1 \: N}}}$

Answer 2

Answer:

Given:

• The velocity of a particle of mass 500 gram changes from 16m/s to 24m/s in 4 seconds. Assuming that a constant force acts on it.

Find:

• Find the magnitude of the force?

Using formulas:

• v = u + at
• F = m * a

Calculations:

⇒ $\rm{24 = 16 + (a * 4)}$

⇒ $\rm{4a = (24 - 16)}$

⇒ $\rm{8 = \cancel{\dfrac{8}{4}}}$

⇒ $\bold{a = 2 \: m/s^{-2}}$

Therefore, 2 is acceleration.

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⇒ $\rm{F = (0.5 * 2) = 1}$

⇒ $\bold{F = 1 \: N}$

Therefore, 1 Newton is the magnitude of force