Question

The velocity of a particle P due east is 4m/s and that of Q is 3m/s due south. What is the velocity of P with respect to Q ?​

Answer 1

Answer: 5 m/s

Explanation: V (PQ) = V(P) -V(Q) (i.e. vel. of P w.r.t. Q)

                                  =4 i cap - 3 (-j cap)

                                  =4 i cap + 3 j cap

                                   =√(16 + 9) = 5 m/s

Answer 2

Explanation:

Given that. Vp= 4m/sec East =4i cap & Vq=3m/sec South= 3(-j) cap then Vpq=?? Vpq= Vp -Vq=4i cap + 3j |Vpq|=5m/ sec