The velocity of a particle v = V₀ + gt + ft² . If Its position is x = 0, at t = 0 ,then its displacement after unit time (t = 1) is [AIEEE 2007]
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Explanation :- Given , v = V ₀ + gt + ft²
After differentiating with respect to time , we get
- dx/dt = V₀+gt +ft²
- => dx = (V₀+ gt + ft²)dt
- so, ₀∫ˣdx = ₀∫¹(V₀+ gt +ft²)dt
- => x = V₀+ g/2+f/3 Answer
Since vertical component of velocity is zero .
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