the velocity of a particle varies with time according to the relation v=at^2
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yess the equation is totally correct but what's the question
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We have, v = at + b/(t + c)
Here, c is added by t , therefore, c = [T]
Again at = LT–1
Therefore, a = [LT–1]/T = LT–2
And [b]/[T] = [LT–1]
Therefore, [b] = [L]
Here, c is added by t , therefore, c = [T]
Again at = LT–1
Therefore, a = [LT–1]/T = LT–2
And [b]/[T] = [LT–1]
Therefore, [b] = [L]
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