Question

the velocity of a particle vary with the timeas v=at^2+bt+c/d+t.find the dimension of constant a,b,c,d​

Answer 1

Answer:

solved

Explanation:

v=at^2+bt+c/d+t

v=at²+bt+c/d+t

dimension of v = L/T   ,

dimension of a = L/T÷T² = L/T³

dimension of b = L/T÷T= L/T²

dimension of c = L = L

dimension of a =1/T = 1/T