CBSE BOARD XII, asked by simadutta5505, 10 months ago

The velocity of a particles is given as v(t) = t3
+ 2t + 1 Find the acceleration of the particle at time t = 1 sec.

Answers

Answered by Anonymous
20

Answer:

v(t) = t3+2t +1

a = dv/dt

a = d(t3 +2t +1 )/dt

a= 3t^2 +2 ...........(1)

the value of t =1 is put in equation (1)

a = 3(1)^2 + 2

a= 3 +2

a = 5 ;answer

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Answered by neel582006
0

Answer:

3+2 = 5

s=5

Explanation:

if the time will be 1 sec then definitely

3+2 =5 will be S

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