Question

the velocity of a point moving in straight line changes according to equation v square =3 t square+2t+1 find the path covered by the point during 10 seconds from the start

Answer 1

V=(3+2+2t+1)m/s

V=6+2t

But,

V=u+at

By comparison

u=6m/s

a=2m/s^2

By 2nd equation of motion

S=ut+1/2at^2

=>s=6x10+1/2x2x10^2

=>s=60+1/2x200

=>s=60+100

=>s=160m

the path covered by the point during 10 seconds from the start is 160m