Question

The velocity of a point moving in straight line changes according to the equation v=(3+2+2t+1)m/s. Find the path
length covered by the point during 10 seconds from the start.

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Answer 1

Answer:

Explanation:

v = (3 + 2 + 2t + 1) m/s

⇒ v = 6 + 2t

But v = u + at.

By comparision,

u = 6m/s

a = 2 m/s²

By 2nd equation of motion

s = ut + 1/2 at²

⇒ s = 6 * 10 + 1/2 * 2 * 10²

⇒ s = 60 + 100

⇒ s = 160 m

Hence the point will cover 160 metres in 10 seconds from the start.

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