Question

The velocity of a retarding body changes from 90 km h$^{–1}$ to 36 km h$^{–1}$. Find the change in its velocity in m s$^{-1}$​.

Answer 1

Answer:

Given that:-

The velocity of a retarding body changes from 90 km h$^{–1}$ to 36 km h$^{–1}$.

To find:-

Velocity in m s$^{-1}$.

Solution:-

Change in velocity in km h$^{–1}$ = 36 – 90 = – 54 km h$^{–1}$

= –54 × 5/18 m s$^{–1}$

= –15 m s$^{–1}$

Thus, change in its velocity in m s$^{–1}$

= 15 m s$^{–1}$.

$\fbox {Extra Information}$

What is velocity?

Velocity is the rate at which the position changes.. The average velocity is the displacement or position change(a vector quantity) per time ratio.

It is a vector quantity.

What is a vector quantity?

A quantity that has both magnitude and direction is called vector quantity.

Some examples of vector quantity are:

• Displacement
• Direction
• Velocity
• Acceleration and many more.

Answer 2

Answer:

here is your answer hope it helps you