the velocity of a train in a particular direction increases tp 60 km/hr from 30km/hr in one minute if the train move with the uniform acceleration during that time what is its acceleration
Answers
Given :
Initial velocity of the car = 30 km/hr
Final velocity of the car = 60 km/hr
Time taken = 1 min = 60 sec
To find :
The acceleration and distance covered by the car.
Solution :
Firstly we have to convert km/hr to m/s
1 km/hr = 5/18 m/s
30 km/hr = 30 × 5/18 = 25/3 = 8.3 m/s
60 km/hr = 60 × 5/18 = 150 / 9 = 50/ 3 = 16. 6m/s.
As we are provided with initial velocity, final velocity and time we can use first equation of motion .i.e.,
v = u + at
here,
v denotes final velocity
u denotes initial velocity
a denotes acceleration
t denotes time
Substituting all the given values in the equation,
➠ v = u + at
➠16. 6 = 8.3 + (a)(60)
➠ 8.3 = 60a
➠ a = 8.3 /60
➠ a = 832/600 = 416/ 300 = 208/ 150 = 104/75
➠a = 1.386 m/s²
Thus the acceleration of the car is 1.386 m/s².
Answer:
1.4m/s²
Explanation:
hope this will help you mate☺