The velocity of a train increases uniformly from 20km-h to 60km-h in 0.2h. The distance traveled by a train during this period?
Answers
Answered by
33
intial velocity u= 20 km /hr=5.56 m/s
final velocity v=60 km/hr=16.67 m/s
the train is under uniform accerleration
t=0.2 hr=12 minutes=720 secs
a=v-u/t=0.0154 m/s²
s=ut+(1/2)at²=7994.88 m=7.99488 km
final velocity v=60 km/hr=16.67 m/s
the train is under uniform accerleration
t=0.2 hr=12 minutes=720 secs
a=v-u/t=0.0154 m/s²
s=ut+(1/2)at²=7994.88 m=7.99488 km
akhileshmaharajas:
but this is not in options
what are the options?
A} 0.2 b}0.4 c}0.6 d}1.2
check ur question if very thing is correct!
yes
wait
it is 8 km sure man wrong options
Answered by
0
The distance traveled by train during this period is 8Km.
Explanation:
The distance traveled is given by
v = final velocity
u = initial velocity
S = distance traveled
t = time
S =
= 8Km
Learn more: velocity
brainly.in/question/11715025
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