Question

The velocity of an electron in the first Bohr orbit of a hydrogen atom is 2.19 X 10 ms. Its velocity in the second Bohr
be
a/438 X 10⁶m/s
b/8.76 X 10⁶m/s
c/5.5 X 10⁵m/s
d/1.10 X 10⁶m/s
​

Answer 1

Answer:

According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of electron=9.1×10

−31

kg

velocity of electron, v=2.19×10

6

m/s

upon substitution we get:

λ=

9.1×10

−31

×2.19×10 .6

6.626×10

−34y

=0.332×10 −9

=3.32×10 −10 m

Explanation:

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