Physics, asked by prafulkamble5621, 1 year ago

The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is v. The velocity of an electron in its fifth orbit will be
(a) v
(b)  \frac{22}{5}\nu
(c)  \frac{5}{2}\nu
(d)  \frac{2}{5}\nu

Answers

Answered by genius1857
3
I hope this question
answer is D
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