Question

the velocity of an object at t=0 is V'= -4j^ m/s.İt moves in a plane with constant acceleration a=3i^ +8j^ m/s². what id the velocity after 1s?

Answer 1

Dear friend,
The solution is provided below :-

Answer 2

If we integrate a the we will get ed +8t+c , then for 1s the the c=3+8=11
Then velocity is 3+8+11=22m/s^2