The velocity of an object becomes doubled then its kinetic energy will be
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Answer:
the kinetic energy will become 4 times
Explanation:
we know,
K.E.= (1/2)mv^2
initial KEi = (1/2)mv^2
new KEf when velocity is doubled = (1/2)m (2v)^2
= (1/2)m(4)v^2
=4 [(1/2)mv^2]
=4KEi
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